How Much Is 5 Teaspoons of Vanilla Extract in Grams?
Converting 5 teaspoons of vanilla extract to grams gives 25.42 g. One teaspoon of vanilla extract weighs 5.08g, so 5 teaspoons is 5 × 5.08 = 25.42g. This conversion is specific to vanilla extract because each ingredient has a different density.
Formula and Step-by-Step
- Start with 5 teaspoons of vanilla extract
- 1 teaspoon of vanilla extract = 5.08g
- 5 × 5.08 = 25.42g
The same formula works for any amount. Multiply (or divide) by the density, then convert units as needed.
Measuring Tip
Liquid densities vary: oils weigh less per cup than water, while syrups and honey weigh more. This is why ingredient-specific conversions matter even for liquids.
Vanilla Extract at Different Amounts
How vanilla extract scales across common teaspoons measurements. Your amount (5 teaspoons) is highlighted.
For reference, 5 teaspoons of vanilla extract (25.42g) is close in weight to an AA battery (23g).
Other Amounts of Vanilla Extract
| Teaspoons | US Grams | Metric Teaspoon | Imperial Teaspoon |
|---|---|---|---|
| 0.25 teaspoons | 1.27 g | 1.29 g | 1.53 g |
| 0.5 teaspoons | 2.54 g | 2.58 g | 3.05 g |
| 1 teaspoon | 5.08 g | 5.16 g | 6.10 g |
| 1.5 teaspoons | 7.63 g | 7.73 g | 9.16 g |
| 2 teaspoons | 10.17 g | 10.31 g | 12.21 g |
| 3 teaspoons | 15.25 g | 15.47 g | 18.31 g |
| 4 teaspoons | 20.33 g | 20.63 g | 24.42 g |
| 5 teaspoons | 25.42 g | 25.78 g | 30.52 g |
| 6 teaspoons | 30.50 g | 30.94 g | 36.63 g |
| 8 teaspoons | 40.67 g | 41.25 g | 48.83 g |
Understanding the Units
What is a Teaspoon?
A teaspoon (tsp) is a US customary unit of volume equal to 4.929 milliliters or 1/3 of a tablespoon. It is the standard measure for spices, leaveners, extracts, and other small-quantity ingredients.
What is a Gram?
Weighing ingredients in grams eliminates the variability of volume measurements. A cup of flour can weigh anywhere from 120g to 160g depending on how it was scooped, but 120g of flour is always 120g of flour.